Error joining HyperV server to Windows 2012 R2 Core w/ HyperV Role cluster


hi,

i have created 2 node cluster windows 2012 r2 core hosts, both hyperv role

i'm trying join 3rd host built hyperv server base o/s can live migration on new hyperv cluster (running on windows 2012 r2 core + hyperv)

whenever try join hv host w2012r2c+hv cluster, recieve error message in event log

"the root\mscluster namespace marked requiresencryption flag. access namespace might denied if script or application not have appropriate authentication level. change authentication level pkt_privacy , run script or application again."

i tried following these instructions not work

http://blogs.technet.com/b/brad_rutkowski/archive/2008/09/08/getting-access-denied-when-trying-to-query-root-mscluster-namespace-remotely-against-windows-2008.aspx

the error message recieve in powershell follows

"[hyperv-host1]: ps c:\users\romoss\documents> gwmi -q "select name mscluster_node" -namespace root\mscluster -computername hyperv-host1  | select-object name

gwmi : there no more endpoints available endpoint mapper.
    + categoryinfo          : invalidoperation: (:) [get-wmiobject], comexception
    + fullyqualifiederrorid : getwmicomexception,microsoft.powershell.commands.getwmiobjectcommand
"

i've disabled firewall on host, follows

[hyperv-host1]: ps c:\> get-netfirewallprofile | select name,enabled | ft -auto

name    enabled
----    -------
domain    false
private   false
public    false

ultimately, goal live migrate vms hyperv-host1 new hyperv cluster. 

our jump host running on hyperv-host1 , without it, going face difficulties managing environment.  hyperv servers , windows 2012 r2 built without management gui

"i have created 2 node cluster windows 2012 r2 core hosts, both hyperv role

i'm trying join 3rd host built hyperv server base o/s"

you cannot mix windows server core hyper-v server in same cluster.  these not seen same operating system, though there high degree of commonality.


. : | : . : | : . tim



Windows Server  >  High Availability (Clustering)



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